blind games [0,1]
A study of blind play.
SB is one chip. BB is two chips. The three chips
will be considered the pot's chips. All fold to
the blinds. This study will restrict itself to
fixed limit. Each players' choices will be initially
limited. The choices will be expanded as the study
processes.
1. SB will raise, bet or check at his turn to act.
BB can call or fold.
1.1. Each player has a stack of four chips. SB
open raises any two, meaning SB raises 100% of the
time. This is the same as a forced raise. BB may
call or fold.
There are 6 chips in the pot on BB's turn to act.
BB is getting 6 to 2 for his call. BB should call
with a LHS of 25 or higher.

SB's expected value of the game.
In the red area of the chart SB wins the blinds.
In the blue area SB loses two additional chips.
In the white the blinds chop the pot.
red= 1/4 X 3 = .75
blue= 1/4 X 3/4 X -3 = -.5625
white= 3/4 X 3/4 X 1 = .5625
SB's EV = 0.75
BB's EV
red= 0
blue= 1/4 X 3/4 X 6 = 1.125
white= 3/4 X 3/4 X 2 = 1.125
BB's EV = 2.25
SB's net EV is 0.75 minus his one chip blind.
His net is minus 0.25
BB's net EV is 2.25 minus his two chips blind.
BB's net is plus 0.25.
Conclusion: SB going all in blind against a
thinking BB doesn't work.
1.2 Each player has a stack of six chips. SB
open raises any two, meaning SB opens 100% of the
time. BB always calls. On the flop SB bets his
remaining two chips. BB may call or fold.
This is the same as both blinds are four chips with
the action starting after the flop. SB has a forced
continuation bet. BB may call or fold.
There are 10 chips in the pot on BB's turn to act.
BB is getting 10 to 2 for his call. BB should call
with a LHS of 16.67 or higher.
SB's EV
red= 1/6 X 5 = 0.8333
blue= 1/6 X 5/6 X -5 = -0.69444
white= 5/6 X 5/6 X 1= 0.69444
SB's EV = 0.8333
SB's net EV is neg 0.16667.
1.3 Each player has a stack of six chips. SB
open raises any two, meaning SB opens 100% of the
time. BB may call or fold. On the flop SB bets
his remaining two chips. BB may call or fold.
There are 10 chips in the pot on BB's turn to act.
BB is getting 10 to 2 for his call. BB should call
with a LHS of 16.67 or higher.
In this game the LHS values remain static. When
BB call prf BB will call on the flop.
SB's EV
red= 1/4 X 3 = 0.75
blue= 1/4 X 3/4 X -5 = -15/16
white= 3/4 X 3/4 X 1 = 15/16
SB's EV = 0.75
SB's net EV is neg 0.25
Conclusion: BB does better by folding hands with
LHS of under 25 prf. *In holdem no starting two
has a LHS less than 32.
1.4 Each player has infinite chips. SB open raises
prf and bets every street. BB forced call prf. BB
may fold on flop and calldown all bets.
18 to 10 for the calldown. BB should call with a
LHS of 35.714 or higher.
SB's EV
red= .35714 X 3 = 1.0714
blue= .35714 X .64286 X -13 = -2.9847
white= .64286 X .64286 X 1 = 0.4133
SB's EV = -1.5
SB's net EV is neg 2.5
Conclusion. This is a very poor strategy for SB.
BB can easily exploit SB by playing passively.
1.5. Each player has infinite chips. SB open raises
prf and bets flop. BB forced call prf. BB may fold
on flop and calldown all bets. SB may bet or check
on the turn/river. The turn/river is an 8 chip bet.
SB bets over 35.714 LHS. BB callsdown with over
35.714 LHS.
SB's EV
red= .35714 X 3 = 1.0714
blue= .35714 X .64286 X -5 = -1.148
white= .64286 X .64286 X 1 = 0.4133
SB's EV = -0.3367
SB's net EV is neg 1.3367
This is a clear improvement over continuely betting
hopeless hands. Maybe micromanaging SB's betting
points will improve SB's EV.
1.6. Each player has infinite chips. SB open raises
prf and bets flop. BB forced call prf. BB may fold
on flop and calldown all bets. SB may bet or check
on the turn/river. The turn/river is an 8 chip bet.
SB bets over 73.193 LHS. BB callsdown with over
35.714 LHS.

SB's EV
red= .35714 X 3 = 1.0714
pink= .26573 X .28572 X 11 = 0.83517
blue= .35714 X .64286 X -5 = -1.148
blue= .28572 X .26573 X -5 = -0.3796
white= .26573 X .26573 X 1 = 0.0706
white= .28572 X .28572 X 1 = 0.0816
SB's EV = 0.5312
SB's net EV is neg 0.4688
Conclusion: SB's EV has gone from -2.5 to -0.4688.
The real solution must be somewhere inbetween.
Either way opening any two with a raise has negative
expectation against anyone who defends his blind.
Note: It's not absolutely clear that my logic is valid.
The LHS of a starting hand remains constant in the [0,1]
game. In holdem the LHS changes with the appearance of
each new board card. Also starting cards catch a piece of
the flop from 32 to 40% of the time. With two unpaired
starting cards missing the flop can make the LHS value
drop drastically.


